Chem341:NMR workshop/Exercise 4d
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Now apply the n+1 rule from above to calculate the multiplicity, where n = the no. of Hs on neighboring carbons.
<quiz> {For the CH2, what is the multiplicity? |type="()"} + Zero || Wrong! Remember it's n+1 - 1 || Wrong! Remember it's n+1 - 2 || Wrong! Remember it's n+1 - 3 || Wrong! Remember it's n+1 - 4 || Correct!
{What do you call a peak with that multiplicity? |type="()"} + singlet || Wrong! Look again... - doublet || Wrong! Look again... - triplet || Wrong! Look again... - quartet || Correct! Now go on to the next question. - multiplet || Not usually with such a low multiplicity, assuming the peak is clean. Look again... </quiz>